Re: PCR Numerical.. Pls HELP
Posted by:
nucleics (IP Logged)
Date: September 08, 2009 09:37AM
This is a difficult question to answer as the amplification efficiency changes throught the whole PCR reaction. Assuming 100% efficiency the answer is 5 x 2^30. In practice, 5 x 1.8^30 is more reasonable.
Daniel Tillett
Nucleics Support